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DQuestion 11 1 pts Which one of the following C1oH14 isomers is matching with 1H NMR data provided below? (delta means unit for chemical shift) delta 0.88 (doublet, 6H), 1.86 (multiplet, 1H), 2.45 (doublet, 2H), 7.2-7.3 (singlet, 5H) A isobutylbenzene B. sec-butylbenzene C. para-isopropyltoluene D. meta-diethylbenzene
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Answer #1

The isomer would be isobutylbenzene. Option A is correct.

Explanation:

Degree of unsaturation = [2+2(C) - H]/2

Degree of unsaturation = [2+2(10)-14]/2 =[22-14]/2 = 4

Therefore, the degree of unsaturation = 4 which indicates the structure might contains three double bonds and one cyclic ring.

2.45 ( doublet, 2H) 1.86(multiplet, 1H) H2 CH3 CH 30.88 (doublet, 6H)

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