The balanced equations for the combustion of butane (C4H10.58.124 gmollis: 2C4H10 + 1302 —> 8CO2 +...

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Answer 1

Answer #1

According to the reaction,

2 moles of C4H10 give 10 moles of water

2×58 = 116 g C4H10 give 10×18 = 180 g water

61.55 g C4H10 give 180×61.55/116 g water

= 95.51 g water

Percent yield of water= mass obtained×100/ theoretical yield

= 43.21×100/95.51

= 45.24%

Answer 2

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