What is the ratio of acetate ion to acetic add (K_ a = 1.76 times 10^-5)...

Question

Question

Answer 1

Answer #1

SOLUTION:

The problem can be solved by Henderson-Hasselbalch equation as:

CH3COOH <--------> CH3COO^- + H⁺

pH = pKa + log [CH3COO^-] / [CH3COOH]

pKa = -logKa = - log 1.76 X 10^-5 = 4.75; pH = 3.570

3.57 = 4.75 + log[CH3COO^-] / [CH3COOH]

log[CH3COO^-] / [CH3COOH] = 3.57 - 4.75 = - 1.18

[CH3COO^-] / [CH3COOH] = antilog(-1.18) = 0.066

Hence the ratio of acetate to acetic acid is 0.066

Answer 2

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