Question

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A fish story: The mean length of one-year-old spotted flounder, in millimeters, is 122 with standard deviation of 14, and the mean length of two-year-old spotted flounder is 165 with a standard deviation of 30. The distribution of flounder lengths is approximately bell-shaped. Part 1 out of 4 Anna caught a one-year-old flounder that was 145 millimeters in length. What is the z-score for this length? Round the answer to two decimal places. Anna's z-score is

Answer 1

Image 1 Mean for One year old flounder u=122 and standard deviation s = 14 z score for x =145 is , z=x-u = 145–122 =1.64 14 Image 2 Mean score for Act is u= 18.8 and standard deviation s=3 z score for x =25 is , z =*=4 = 25–18.8 = 2.07 Image 3 Population mean u = x/N=7277.1/15=485.1393 N 15 Population variance = (*_*)2 = 915,75 = 61.050 Population standard deviation o=V61.0503 =7.814

Image 4 Using the empirical rule distribution 95% of the data fall between (40.41 and 52.05) it is 2SD of the mean 5% of the data fall out side of the interval (40.41, 52.05) since the distribution is symmetric hence 2.5% of the data fall less than 40.41 Approximately 2.5% of the amount were has less than 40.41 Or Given mean u=46.23 standard deviation s=2.91 P(x<40.41) = P(*** < 40-42.46.23) =P(Z<-2.0) =0.0228 Approximately 2.28% of the amount were has less than40.41 2.91 Image 5 Mean of this income = x/n=977/25 = 39.08 thousand dollars