A sample of paramagnetic material is located very close to a bar magnet, in a region in which the field of the magnet appears almost uniform over small distances. If the magnet is suddenly pulled away from the sample so that the sample is no longer in the quasi-uniform region of the magnetic field, how will the sample respond? a) the sample will accelerate towards the magnet b.) the sample will move toward the magnet at constant speed c.) the sample will accelerate away from the magnet d.) the sample will remain at rest
A paramagnetic sample means it has the property to get magnetized as per the external magnetic field and here the external magnetic field is the magnetism applied by the bar magnet.Sudden removal of the bar magnet means the removal of external magnetic field for the paramagnetic material.But we know that paramagnetic material alway get magnetized in the same direction as the external magnetic field .so due to removal the paramagnetic material also get moved toward the bar magnet as both have same direction of magnetism .so option a is correct ,the paramagnetic material will accelerate towards the bar magnet .
A sample of paramagnetic material is located very close to a bar magnet, in a region...
answer all Q pls 8. A bar magnet is dropped through a loop of copper wire as shown. Recall that ou magnet, magnetic field lines point away from a north pole and toward a south p positive direction of the induced current I in the loop is as shown by the arrows on the loop, the variation of I with time as the bar magnet falls through th by which of the following graphs (the time when the midpoint of...
I need help to write a nice introduction for experiment 6 please ( no hands write ) typing Thank you HEAT TREATMENT OF STEELS EXPERIMENT 6 EXPERIMENT 6 HEAT TREATMENT OF STEELS THEORY The Effect of Cooling Rate One of the most convenient methods for controlling the properties of a given steel, i.e., a steel whose composition is already fixed, consists of austenizing the steel and ten cooling to room temperature at some predetermined rate. A variation of cooling rates...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...