Question

PartA A given system has the equipotential surfaces shown in (Figure 1). What is the electric potential at the point (3.0 cm, 1.0 cm)? Express your answer to three significant figures and include appropriate units. Figure 1 of 1 alueUnits y(cm) Submit Part B How much work is done by the electric force when a 0.10-C charge is moved from the point (3.0 cm, 1.0 cm) to the point (4.0 cm, 5.0 cm)? Express your answer to two significant figures and include appropriate units. V = 30.0 V x (cm) 6 8 10 V = 20.0 V alueUnits V = 10.0 V V 0.00 Submit

Answer 1

Use the relation between electric field and potential difference to find electric potential at the given point and work done by electric force after finding the potential difference between the two points as shown below

A) Ex = -Que. - (VC4cm) - V()) - 4cm-0 = -250 v/m 0.04m-0 By late -(veco- vB) = -10v-ow? 2 = - 500 V/m So, ² = - 250 î - 500 Î V/m Now, Av=-EAR a = o ê to } at origin of = 3cmi tlcmî at (3cm, 1cm) = 0.031 +0.01 Î m so 88 = 888 = 0.031 +0.025 (oitof) = 0.031 +0.01 Îm so AV = -1-250 - 5003). (0.03 7 +0.013) V6-vC) - 250X0.03 + 500X0:01 = 12.5 3) V-0 = 12:5V - Vf = [12 5v B) Here, ti = o-osê +0-01 ſ P = 0.04 @ +0.05 AV = EA7 --- (-12) = -(-250 î-sooj) (0-04ĉ to osì -(0-03î + 0.0)) = (250î + 5003)(0.01ê +0.045) = 22.5 V W = -AU -9 AV: -0.10) (22.5V) =E 2.25