Question

To understand how to quantitatively determine whether a particle is in a state of mechanical equilibrium. In statics, we make extensive use of Newton's first law, which states that a particle, initially at rest, or moving in a straight line with constant velocity, will remain in its current state unless the particle is subjected to an unbalanced force system. If the sum of the forces acting on a particle is zero, then it is in mechanical equilibrium. Although a particle is most likely at rest when in equilibrium, it could alternatively be in a state of constant motion. Part B As shown, three forces, F1, F2, and F3, act at the same point on an object. (Figure 2) The point of application is the o y-z plane and is described by an angle B, = 29.0 degrees. F2 is in the x-z plane and is described by integer lengths zero, what is the magnitude of F3? Express your answer numerically in kilonewtons to three significant figures. • View Available Hint(s) F = 21.5 kN Previous Answers Submit v Correct Significant Figures Feedback: Your answer 21.54 kN was either rounded differently or used a different numb Part C Figure What are the angles a3, B3, and Yg for the force F3 = 13.8i + (-16.2j) + (3.20k) in Part B? (Figure 3) <) 3 of 3 Express your answers numerically in degrees to three significant figures separated by commas. • View Available Hint(s) F2 F3 να ΑΣφ vec 12 a3,B3. Y3 = degrees B1 Submit

F1=16.18j-8.97k

F2=-13.85i+5.77k

Answer 1

Paet : B R= 16.18)- 8.97k, = -13. 85i +5.77k. Fit Fit Fg = 0. 16-18j–8.97k - 13-851 +5.77k +F3 = 0. F3 = 13-851 - 16:18j + 3.2 k. Fg = J03.853+ GI6183+ (3-23² %3D F3 = 21.54 kN Fx Cosd3 = 13.85 Part :C 21.54 d3 = cos" ( 13.85 >3= 49.97° 21.54 Fy -16.18 21.54 -16.18 21.54 > B3 = 138-69° 3.2 %3D 21-54 d3 = los" () >3= 81.45° 3.2 21.54