2. (1.5 Credits) a. One carbon in Compound A is an alpha carbon and beta carbon....
pppppplllleeeaaassseee help 1. a. Compound 1 reacts with A under acid conditions to form an imine. What could Z be in this reaction? b. Compound 2 reacts with A (same A as previous reaction) under acid conditions to form an amide. What is Z in this reaction? Draw the structure of A Use curved arrows to show how Compound 2 forms the amide. c. Both reactions involve a leaving group. What is the leaving group in each reaction? O A...
7.27 For each of the steps in Problem 7.26, determine whether the product can eliminate a leaving group to produce a compound that is different from the reactants. For those that can draw the appropriate curved arrows and the new product that forms. 7.26 Draw the curved arrows and the product for each of the following nucleophilic addition steps. (b) 0 CHOK ? [ S + CHLI ? land L CHOK A MgBr (d) No. ooo? " Nabte —> ?...
a. First, circle the leaving group and label the alpha carbon as a. b. Then, label the adjacent sp3 beta carbons as B. c. Finally, draw in the H's that can get eliminated along with the leaving group in each of these compounds. The first compound has been completed for you. HH می ) و CH3 2. Now, let's perform the elimination to make the Zaitsev (most substituted) product. Draw in the H from before and the curved arrows to...
Help 1. Under acidic conditions, if Z CH3 in Compound 2, Compound 1 forms. он он о 2 3 a. If ZCompound 3 forms Identify Z and determine reaction condition A. b. Use curved arrows to show how Compound 3 forms from Compound 2 using your Z and reaction condition A from Question 1a c. How does Z determine the product that forms? 2. Ambien is a prescription sedative. Draw the structures of the metabolic (hydrolysis under acid conditions) products...
PLEASE ANSWER ALL QUESTIONS Question 5 The reaction below occurs via SN2 and E2 reaction mechanisms. The question only requires you to address the E2 reaction only. For the E2 reaction: Use Newman projections to show the relationship between the leaving group and the beta-hydrogen on the carbon labeled with the asterisk ("). 1. If the leaving group and the beta-hydrogen on the carbon labeled with the asterisk (1) are not in the correct orientation, show the result of the...
Organobromine compounds are used in fire retardants, fumigants, and biocides. 2-bromo-3-methylbutane reacts with Substitution Product Elimination Product Br a. Identify the alkyl bromide as 1°, 2°, or 3° b. Identify the nucleophile as strong or weak and big or small. c. Draw the structures of the substitution and elimination products. Use curved arrows to show how the elimination products form. d. Which product is major product? Give reasons. e. If C2HsOH is used instead of C2HsO, will the same major...
Although there are two different bromines in the below compound beta to a proton, only one of them can be eliminated in this reaction. Instructions: Your job for this case study is to investigate why only this product forms. A a hint, look up orbital interactions for elimination. Use arrows as well as the proper chair form to show the elimination mechanism. Please explain your answer. Br NaOEt Br HOEt
5. For the following reaction step, indicate which pattern of arrow pushing it represents. Circle one. -Ogr Br A. proton transfer C. nucleophilic attack B. loss of leaving group D. rearrangement 6. The following reaction has three mechanistic steps (down, across, and up). Draw all of the curved arrows necessary to complete the mechanism. (Hint: there should be 4 arrows total.) HBO OH Br H-Br OH2 + H₂ö:
CH3 CH2 Secondary amines add to aldehydes and ketones to give enamines. Enamines are formed in a reversible, acid-catalyzed proces nucleophilic addition of the secondary amine to the carbonyl group, followed by transfer of the proton to yield a neutral carbinolanine Prosonation of the hydroxyl group converts it into a good leaving group, is no Instead, a proton is lost from the neighboring carbon to form an enamine. p, however there is no hydrogen left on the nitrogen to be...
Help on all parts of question 3 would be greatly appreciated! 3. Treating alkene "A" below with HBr can lead to a number of products. "A" + H-Br A bunch of products. For real, hella products. 3.A. Label the stereocenters in compound "A" as R or S and label the alkene as E or Z. 3.B. Draw the curved arrow mechanism leading to the most stabilized carbo- cation intermediate. (don't do any rearrangements, just acid/base with the alkene) H-Br most...