Question

How do i find the p- value with a distribution table or TI 84 ???

A health journal conducted a study to see if packaging a healthy food product like junk food would influence children's desire to consume the product. A fictitious brand of a healthy food product-sliced apples-was packaged to appeal to children. The researchers showed the packaging to a sample of 402 school children and asked each whether he or she was willing to eat the product. Willingness to eat was measured on a 5-point scale, with 1 = "not willing at all" and 5= "very willing. The data are summarized as x= 3.42 and s=2.04. Suppose the researchers knew that the mean willingness to eat an actual brand of sliced apples (which is not packaged for children) is p=3. Complete parts a and b below. a. Conduct a test to determine whether the true mean willingness to eat the brand of sliced apples packaged for children exceeded 3. Use a = 0.01 to make your conclusion. State the null and alternative hypotheses. Ho: p=3 He: p>3 Find the test statistic. z= 4.13 (Round to two decimal places as needed.) Find the p-value. p-value = (Round to three decimal places as needed.)

Answer 1

Ans:

Test statistic:

z=(3.42-3)/(2.04/sqrt(402))

z=4.13

p-value=P(z>4.13)=1-normsdist(4.13)=0.000

(you can use excel function normsdist(z),which return the cumulative probability of normal distribution)

For Ti-84 calculator:

Use normalcdf(z_calc,1000,0,1)