Question

What minimum speed does a 190 g puck need to make it to the top of a 3.20 m -long, 29.0 degree frictionless ramp? Express your answer with the appropriate units.

Answer 1

given data is m = 190 g = 0.190 kg

length L = 3.2 m

angle $\theta$ = 29⁰

we have h = L sin $\theta$

here h is height of th ramp

h = 3.2 X sin29

h = 1.55 m

and conservation of energy that

or equilibrium is KE = PE

1 / 2 m v² = m g h

h = v² / 2 g

1.55 = v² / 2 X 9.8

v² = 2 X 9.8 X 1.55

v² = 30.38

v = 5.511 m/s