Question

3. What type of energy will be available in radio transmitter antenna? Explain. (1.5) 4. Explain the relationship between K.E.P.E versus time according to principle of conversation of energy. (1.5)

pls Answer the questions 3 and 4

Answer 1

3. A radio transmitter is an essential part of communication devices such as televisions, walkie talkie, cell phones etc.

A radio transmitter is an electronic device which produces radio frequency alternating current. This alternating current is then passed to an antenna. Now the antenna when subjected to radio frequency alternating current, gets excited and starts radiating radio waves. These radio waves are then used for broadcasting and signal transmission.

Precisely talking about antenna as asked in question, a radio transmitter antenna converts Radio frequency alternating current to radio waves i.e. electronic energy to wave energy/ electromagnetic energy.

4.

Talking about the relationship between kinetic energy, potential energy versus time , there is no specific relationship between them. But I will try to explain with an example.

First of let me tell you that Kinetic energy is an energy due to motion of the object while potential energy is an energy due to position of the object.

Kinetic energy is given by the following expression

K.E = ½mv²

Where K.E. is the kinetic energy,

m is the mass of the object and

v is the velocity if the object at which it is moving

Similarly , potential energy is given by the following expression

P.E. = mgh

Where, P.E. is the potential energy

m is the mass of the object

g is the acceleration due to gravity and

h is the height of the object from the datum.

Now the sum of these energy is said to be constant irrespective of internal energy.

i.e. K.E. + P.E. = Total energy

And according to the law of conservation of mass this total energy remains constant.

Now consider the following illustration

olmgh и | Ögh + 1 mv? от my,-

In the illustration above , a ball is thrown from the top of a building whose height is H. Initially at time t=0, the velocity of the ball was zero so kinetic energy is zero and potential energy is maximum. Now as the ball goes down to a height h , in time t​​​​​​1​​​​​ and the decrease is height causes decrease in the potential energy, however the ball has now velocity v​​​​​​1​​​ . So potential energy is decreased and kinetic energy is increased here, in such a way that sum of both energies is constant. Finally the ball hits the ground after time t​​​​​​2 , where height is zero so potential energy becomes zero amd the ball attains its maximum velocity. At this position the ball has maximum kinetic energy which will be equal to the total energy of the ball. Therefore this example satisfies law of conservation of energy.

Furthermore there can be a mathematical proof that the energy is conserved in this situation. However we don't need this here. This discussion is enough to explain the relationship between K.E. ,P.E. versus time.