Question

Name College Algebra Review Polynomial Functions Solve each sentence. LE1272 1. 0.5x2+3x-33 2. 3x2-10x-5 3. x2-2x--6 4. x = 43x-12ND 5th +8x-3 6. 052-328 5. 3 7 Write a quadratic equation whose solutions are:

Answer 1

solution given: (1) 0.50 +32 233 5n²+ 3n-33=0 → use quadratic formular Gay Coff. of n27 03-6+ 6-901 b-> (oft. 0 x 29 Le Coff, odnos 915,6-3, (5-33 n=-(3) + 13)-445) (-33) 21 ) n= -3 I 19 +66 x = -3 7 575 ne-328.66 4 n=-3+8.66 | na-3-8.66 n=5.66 I n=-11.66 (n= 5.66,-11.66) (2) 3 m²=lon-s 3n²lon +5=0 → by quadratic formula a=3,6=-10 (=5 x = -1-10) + Hop_4(3/15) 273 e na lotno-60 n= 10t Tuo n= lot 6.32 n=10+ 6.32 jon: 10-6.32 na 2.72 na o.bl In = 0.60,2427

3. n%2n=6 n²-2n-6=0 9=1 6=-2, (= -6 n=-(-2) + √(2²-4(1)(-6) 2X1 x = 2 + √4+24 2 na 2 1 128 na It I X21+ Eg+2.64 In = 3.64 n = 1- = 1-2.64 1 xz - 1.641 x=-1.6+, 3.64 n 43n-12 p2-43n+12=0 az 1 bi-483, 2 =12 → use quadratic formula g=-1-455) ± √(-4f51²-4(1) (12) 2x1 4632 Jug - UB ne = 23to N2 283, 23

s. ² ton=3 n²tzun-gzo b=24, a1,-9 use quadratic formula n = -24 t (124) 4(1)(-9) 200 n u e 1576+36 n=-24 t 1612 2 x= -12 t 1st n = 12 + 12.36 n=-12 + 12.36 In=-12- 12.36 In = 0.361 Ir=-24.36 -> -2436,0.36 0.5n²+3n < 28 0.50² +37-28 co q=0.5, 6:3, (:-28 sa - 3t √3)²-4 (²5) (-28) 24.5 = -3 I 19:56 n = -3 + 165 n=-3+8.06 x 2-3-8.06 n = 5.06 I n=-11.06 (n-5.06)(n+ 11.06) To ne [-1.06,5.06]