Question

the figure below is made up of three identical overlapping circles and one equilateral triangle. Given that the area of the triangle is 63cm^2 and the radius of circle is 7cm. Find the area of the shaded part B (take pi=22/7)

16. The figure below is made up of three identical overlapping circles and one equilateral triangle. Given that the area of the triangle is 63 cm2 and the radius of each circle is 7cm, 22 b) Find the area of the shaded part B (Take it ) 7

Answer 1

Since the given Triangle is an Equilateral Triangle, therefore, the point of Intersection of the Three Circles, which is Inside the Circle and the Triangle will be the Center of the middle Circle.

We will Divide the Equilateral Triangle into Three Sub-Equilateral Triangles as Follows:

$1595099177416_image.png$

It is given that the Area of the Triangle is 63 cm².

Therefore Area of One-Third of the Triangle will be:

$\frac{1}{3}*63=21 \ cm^2$

It is Given that the Radius of the Circle is 7 cm².

Therefore, Area of the Circle is:

$\pi*(7)^2$

Similarly, Area of One Third of the Circle is :

$=\frac{1}{3}*154 \ cm^2$

= 51.33 cm² .

Substract the Area of Third of the Triangle from Third of the Circle:

51.33 - 21

= 30.33 cm² .

But we have to Deduct the Area of One Third of the Triangle again to get the Desired Results.

30.33 - 21

= 9.33 cm² .