We know that the Force between the two charge
F=kQq/r^2. ...1
According to the question R =2r
Put in above equation
F' =kQq/(2r)^2
F' = kQq/4r^2 ...2
From equation 1 and 2
F' =F/4
here F=3.5×10^(-2) ( first varify red digit it is not so clear )
So
F' =3.5×10^(-2)/4
F' = 0.875×10^(-2) N. Answer.
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