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What is the maximum number of water molecules pr
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17. from the data given we can do the following:

7.5gN_2O_3*\frac{1mol}{108g}*\frac{4molNO_2}{2molN_2O_3}*\frac{46gNO_2}{1molNO_2}= 6.4gNO_2

18. We can do the following taking into account that a stable molecule has an oxidation state = 0

Na = +1

ClO2 = -1

we can gladly help you with the others but you should post them again

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