Question

17. (a) A desktop laser printer has a 300 dots-per-inch resolution. If each dot is stored in one bit of memory, how many MiB of memory are required to store the complete image of one 8.5-x 11-inch page of paper? (b) How many MiB of memory are required for a 1200 dots- per-inch printer?

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Answer #1

(a)
dot frequency = 300 dots per inch
resolution = 8.5 * 11 inch = 935 inches

So,total number of dots = 300 * 935 = 280500 dots

1 dot = 1 bit

Memory occupied =
280500 dots = 280500 bits = 0.02805 MBits

(b)
If dot frequency increases = 1200 = 300 * 4 per inch

Therefore,
Memory occupied - 0.02805 * 4 = 0.11220 MBits

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