Part 1:
Decision Variable
HCD = no. of interviews of household with children in day time
HCE = no. of interviews of household with children in evening time
HND = no. of interviews of household without children in day time
HNE = no. of interviews of household without children in evening time
Objective Function:
Objective function of the problem is to minimize the total cost of interviews:
Cost = cost per interview x no. of interviews
Minimize Z = $20HCD + $25HCE + $18HND + $20HNE
Subject to:
Sr. No. |
Constraint |
Equation |
1 |
Total 1000 interviews are to be conduct |
HCD + HCE + HND + HNE = 1000 |
2 |
Interview at least 400 households with children |
HCD + HCE >= 400 |
3 |
Interview at least 400 households without children |
HND + HNE >= 400 |
4 |
Total evening interviews >= total day interviews |
HCE + HNE >= HCD + HND - HCD + HCE - HND + HNE >= 0 |
5 |
At least 40% of the interviews for household with children must be conducted during evening |
HCE >= 0.4(HCD + HCE) -0.4HCD + 0.6HCE >= 0 |
6 |
At least 60% of the interviews for household without children must be conducted during evening |
HNE >= 0.6(HND + HNE) -0.6HND + 0.4HNE >= 0 |
7 |
Non-negativity constraint |
HCD, HCE, HND, HNE >= 0 |
Part 2:
Excel Model:
Optimal Solution:
No. of interviews of Household with children in day time = 150
No. of interviews of Household with children in evening time = 250
No. of interviews of Household without children in day time = 171.4
No. of interviews of Household without children in evening time = 428.6
Total Cost = $20,907.14
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