We know, F=mg
Given, m=300 g = 0.3 kg
Therefore, F = 0.3 * 9.8 = 2.94 N
Correct answer is option B.
RESOLUTION OF FORCES 25. In the resolution of forces experiment, horizontal forces were produced by hanging...
A 10 kg object on a frictionless table is subjected to two horizontal forces, F1 and F2, with magnitudes F1 = 22 N and F2 = 38 N, as shown in Figure 4-28. 10kg 30 Figure 4-28 (a) Find the acceleration a of the object (0.3 (b) A third force F3 is applied so that the object is in static equilibrium. Find F3 x i)m/s2 i1.64545 X (-41 x i) N |-32.909
A 10 kg object on a frictionless table...
A 10 kg object is subjected to two forces F1 and F2. F1 has a magnitude of 20 N and acts straight upward and F2 has a magnitude of 30 N at 30 degrees below the horizontal from the positive x axis. Find the acceleration of the object. A third force F3 is applied so that the object is in static equilibrium. Find F3.
Three forces act on an object, with force F2 acting in the positive x direction. (a) Find the magnitude of the net force acting on the object? (b) Find the direction of the net force. The angle is measured from the positive x axis. (c) Find the fourth force that a person would have to exert on the object to make the net force equal to zero. F1=11.0N at an angle of 40 degrees above the horizontal F2=12.0N F3=10.0N along...
A mass of 7 kg is resting on a horizontal, frictionless surface. Force 1 is applied to it at 23 degrees below the horizontal, force 2 has a magnitude of 19 N and is applied vertically downward, force 3 has a magnitude of 3 N and is applied vertically upwards, and force 4 has a magnitude of 21 N and is applied in the-x direction to the object. When these forces are applied to the object, the object moves 9...
Forces F1, F2,and F3 act on the structure of the figure, shown in an overhead view. We wish to put the structure in equilibrium by applying a fourth force, at a point such as P. The fourth force has vector components h and r v . We are given that a 2.03 m, b 3.07 m,c1.71 m, F1 -13.7 N, F2 16.1 N, and F3 3.58 N. Find (a) magnitude of Fh (b) magnitude of Fv, and (c) d (a)...
Two known forces F1 = 2.80 N at 76.0 o below the positive x-axis and F2 = 2.80 N at 32.0 o above the negative x-axis are acting on an object. (a) What is the magnitude of the third force F3 so that the acceleration of the object is zero?
Two known forces F1 = 2.80 N at 76.0 o below the positive x-axis and F2 = 2.80 N at 32.0 o above the negative x-axis are acting on an object. (a) What is the magnitude of the third force F3 so that the acceleration of the object is zero?
Consider a right triangle of mass 6.69 kg and sides a=2.1 m and b, shown in the picture below. The triangle is pivoted at the corner at the top, as shown, with four forces , F1=16 N, F2=16 N, F3=15 N, and F4=15 N acting on it. The angle a=27 degrees. What is the z-component of the torque exerted on the triangle by force F1? у Axis of rotation х FA a F1 a 90° a b α F2 F3
The two forces F1 and F2 shown in the figure(looking down) act on a 22.0 kg object on a frictionless tabletop.If F1 = 10.6 N and F2= 16.2 N, find the A) angle of the net force on the object for (a). B) absolute value of the net force on the object for (b). C)angle of the net force on the object for (b). D) acceleration of the object for (b).
Chapter 12, Problem 015 Forces F1 F2, and F3 act on the structure of the figure, shown in an overhead view. We wish to put the structure in equilibrium by applying a fourth force, at a point such as P. The fourth force has vector components F h and F v . We are given that a= 0.755 m, b 3.85 m, c = o.535 m, F1 = 11.6 N, F2 = 13.3 N, and F3 = 2.43 N. Find...