Question

2. Obtain A (open loop gain), B (arbitrary rate), and Af (closed loop gain) of the transmission feedback amplifier below. (gm1 = gm2 = 5 MAN, RD = 10KOhm, ro2 = 20KOhm, RF = 1000hm, RL=1KOhm), and Ignore ro1 and consider ro2 only when calculating output resistance. Calculate using each transistor's small signal model... SRO (Q2 that SRL Vs RF

Answer 1

Vqz The small signal equivalent circuit is deawn as Open loop gain Aa To -0 * Amy Upsi & RD Vsqz Ro Io = 4m2 Veqz Amylaz 출 & RF RE ger = Vs Vs Vsqz = amil imi me Vsqz = Usz – Uq2 = 0-6-Am, ! 9-6, Man , Ro) 2 KUL at finput → – Vs + Upsi + 4m, Ups, RF = 0 + 195,= HIMPF using equation & in > Vsqz Ro t/m RF using equation ☺ In ☺ A= Io Ro 1+ RF Sx107x Sx 10 10x103 0.167 = 167 malv 1+ 5x10*x100 The feedback ß network is drawn as B = V RE = 100 (%) Io Ig 167ml Ap = 9.44 malv ITAB 1 +0.167) (100) Us => A = TH 130 IORE A