Question

26. A hoop (i.e., a ring) of radius 5.2 m and mass 12 kg is suspended from a pivot on the perimeter of the hoop as shown in t

I dont know how to work it through.

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Answer #1

time period T = 2*pi*VI/mgt (physical pendulum formula)

I = moment of inertia of ring about point of suspension = mr2 + mr2 = 2*m*r2

length l = distance of point of suspension from center of gravity i.e from center = r

so T = 2*pi* 2* m* r2/mgr = 2*pi* V2*r/g

angular frequency = 2*pi/T = V9/2r = 9.8/2 * 5.2 = 0.97 rad/s

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