Question

A Boeing 747 jet airplane lands on a runway traveling at 290 km/h and decelerates uniformly to rest in 11 seconds. [2 pts] a) b) Calculate the plane's deceleration in m/s2. Calculate the distance the plane traveled down the runway after landing.

Answer 1

To calculate deceleration and distance traveled by a plane before coming to rest on landing

Initial velocity, uz 290 km/h z 290x lodo m/s 80555 m/s Let the deceleration bet Final vclocity, vzamis - Time taken to stop t zils From uzu- ft, - 2 80555 - 0 2 7.323 m/s ~ 7.32 m/s² a) : deceleration of the plane z 7.32 m/s2 (Answer) Let the distance moved after landinto come to a stop be s Then from, we u 2-2fs sa un uz 2 80.555202 2 x 7.32 3. 80.555? 2X 7°03 23 2 443.06 m 443'1 m distance tranded on the runway coming to stop z 443.1m