Question

This was a question on my most recent chemistry exam, I did the best I could but habw no idea if I did this correctly. No matter what I tried I couldn’t find my answer in the choices but I got close a few times. My professor has a bad habit of rounding numbers so I susspect thay she may have rounded the 80.1°C to 80°C when she was creating the answer choices on the exam. Will someone please work this question so I can see if I worked it the correct way? Thanks in advance!

20. The heat of vaporization of benzene, CH , is (Molar Mass - 78 g/mol) 30.7 kJ/mol at its boiling point of 0.1 °C. How much energy in the form of heat is required to vaporize 102 g benzene at its boiling point? a. 0.302 kJ 2 Vaporiterion m * AH v ritetin 2 gasm.coAT b 2 energy changes (9.) 24.2 Ki nanges d. 40.1 kJ e. 3.14 x 10 kJ 30.7 = 1024 x 4d Vép T02 Toi 5.30098*80.1=24.108

Answer 1

- Heat of rupourisation of benene = 30.7 kJ) mole : Dreng This means Armount of energy required for more of bussene to repourize at its boiling is point 30.7 kJ. 80.1 C rastar mass of benene = 78.0 gm more Given mass of bemene: 102 gm. :. pololes of verene : 102 grm 78 i Amount = 1.3076 miles of benene of energy (Meat) required 1.3076 mores bersene = 1.3076 more x 30.7 kJ/mole Drag = 40.146 KS 1. Answer d} 40.1 kJ