Answer - Path 2 is the correct answer
Explanation
When the charged particles beam enters in the magnetic field, the beam will experience Lorentz force. the Lorentz force is given by
Where q is the charge, v velocity and B is the uniform magnetic field.
In the case of Electron beam q = -e then Lorentz force is given by F= -e (vxB), this force acting downward as shown in figure 1 in case of the electron beam.
Now we take when the proton beam with the same velocity enters into the magnetic field, the Lorentz force is given by, F= e(vxB) because of q= e for proton. In the case of proton Lorentz force act on the beam upward.
In figure II there are two paths of the different radius of curvature, which are going upward. The path 1 having a radius of curvature equal to the radius of curvature of electron path in figure 1 and path 2 has different value radius of curvature.
The radius of curvature is defined by
From the above equation, we can say that for the uniform magnetic field, the radius of curvature is directly proportional mass. in case of proton radius of curvature more because proton has more mass than an electron(mp>me)
So path 2 is the correct answer
thank you !!
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