Homework Answers
Ans a. The probability of a random person being affiliated with party B can be found by summing up all the entries in the row of Party B
P(B) = 0.16 + 0.12 + 0.14 = 0.42 (The answer can be found by summing up the entries in the 2nd row)
Ans b. The probability of a person being affiliated to some party is equal to the sum of prpbabilities of a person being affiliated to party A, B and C.
Thus, P(some party) = P(A) + P(B) + P(C)
Now, P(A) = 0.12 + 0.09 + 0.07 = 0.28 (The sum of the entries of the first row)
P(B) = 0.16 + 0.12 + 0.14 = 0.42 (The sum of the entries of the second row)
P(C) = 0.04 + 0.03 + 0.06 = 0.13 (The sum of the entries of the third row)
Thus, P(some party) = 0.28 + 0.42 + 0.13 = 0.83
Ans c. The probability that a random person is in favour of the bond issue can be found by summing up the entries in the first column, ie the column of entries in favour of the bond issue. Thus :
P(favour of bond issue) = 0.12 + 0.16 + 0.04 + 0.08 = 0.40
Ans d. The probability that a random person has no party affiliation and is undecided about the bond issue can be found at the intersection of the "None" row and "Undecided" column.
Thus, P(no party affiliation and undecided about bond issue) = 0.03
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