Question

х STRENGTH OF MATERIAL FINAL (2020).pdf - Adobe Reader File Edit View Document Tools Window Help 139% *** Find Q1 A simply supported beam having a span length equivalent to last 4-digit of your student no. (mm). The beam is carrying uniform distributed load having intensity of last 2- digit of student no. (N/ mm) that span from the origin to two third of the entire span, together with concentrated load of 50N at the mid-span of the beam. The beam cross-sectional details are; . Beam type = inverted Tee flange beam Flange Length = Last 3-digit of student no. (mm) Flange thickness = 20mm Web height = First 3-digit of student no. (mm) Web thickness = 20mm Answer the following questions a) Sketch the beam with its cross-section. (5Marks) Activate Windows Go to Settings to activate Windows e b) Determine the shear force and bending moment at critical location (5Marks) o Type here to search 11:27 AM 6/30/2020 D
ID number 161203029

Answer 1

14.5 126.75mm Centeroid 15445 22:25 50N 29 Huam monthne 151415 » AK -3029 mm B 20.19.33 mm (Beem) Student Id is 1612 3029 11 1 Qonam K K 29 (Cronection) श b) RA A Rp - So + 29 (2019:33) 56610067N = 58,61 km How EMA -) RB (3029) – 50 (1514.5) – 29 (2019:33) - RB = 19545.2 N or 19.55 KN RA 58.61- 19.55= 39.96kn. Shear force at B-R = - 19.55 kn. D = -19.55+ 29 (504.83) + 50 sf at intermediate beint between a gly = -19.55+ S0 + 25x{262-1) 13 or - 4.86 KM lovo 000 10200 1701 KN

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