Question

A spring with spring constant 12.5 N/m hangs from the ceiling. A 550 g ball is attached to the spring and allowed to come to rest. It is then pulled down 6.50 cm and released.

What is the time constant if the ball's amplitude has decreased to 4.00 cm after 43.0 oscillations?

Express your answer with the appropriate units.

The answer is not 118.74 s^-1

Answer 1

It is time constant Time period te 292 Time for 43 oscillation Swe_i = 43 T Amplitude decay as A = A et A=4 cm Do = 6:5 cm 0.4855 3 x 200 Sw?z?-T wo = Stwo-525 D wo? = 22-23 556-2 = J 22-232?_ 309369.7+1=22.7323 Le = 116.665 )