Question

1. Determine the following: a. The inner diameter of 8 Schedule 80 pipe. b. The roughness ratio of a commercial steel 6 Sch
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Answer #1

Part a

For 8" Schedule 80 pipe

Outside dia Do = 8.625 inch

Outside radius Ro = Do/2 = 8.625/2 = 4.3125 inch

Thickness t = 0.500 inch

Inside Radius Ri = Ro - t

= 4.3125 - 0.500

= 3.8125 inch

Inside dia Di = 2*Ri = 2*3.8125 = 7.625 inch

Part b

Roughness of commercial steel pipe

e = 0.045 mm

For 6" Schedule 40 pipe

Outside dia Do = 6.625 inch

Outside radius Ro = Do/2 = 6.625/2 = 3.3125 inch

Thickness t = 0.280 inch

Inside Radius Ri = Ro - t

= 3.3125 - 0.280

= 3.0325 inch

Inside dia Di = 2*Ri = 2*3.0325 = 6.065 inch x (25.4mm/inch)

=154.051 mm

Roughness ratio = e/Di

= (0.045 mm) / (154.051 mm)

= 0.0002921

Part c

Reynolds number Re = 600,000

Roughness ratio = e/Di = 0.005

From Moody's chart at given conditions

Re is represented by point C

e/Di is represented by point B

Intersection point is A

Fanning friction factor is represented by point D

Fanning friction factor f = 0.0305

Moody Diagram 0.09 Transition Region 0,08 0.07 0.06 ... 0.05 0.01 0.03 0.05 0.002 0.010 0.04 0.01 Friction Fnctor Laminar Flo

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