Question

Use Lewis theory to determine the formula for the compound that forms between each of the...

Use Lewis theory to determine the formula for the compound that forms between each of the following pairs of elements.

PART A.

Ca and Te

Express your answer as a chemical formula.

PART B.

Ba and Cl

Express your answer as a chemical formula.

PART C.

K and Te

Express your answer as a chemical formula.

PART D.

In and O

Express your answer as a chemical formula.

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Answer #1

Part A:

Electronic configuration of Calcium: [Ar]4S2

Electronic configuration of Tellurium: [Kr]4d105S25P4

Calcium has 2 valency electrons and to get octet configuration, it has to lose 2 electrons.

Tellurium has 6 valency electrons and to get octet configuration, either it has to lose 6 electrons or gain 2 electrons.

Calcium loses two electrons and Tellurium gains these two electrons. Both the atoms, Calcium and Tellurium gets inert gas configuration.

It's formula is CaTe

Part B:

Electronic configuration of Barium is [Xe]6S2

Electronic configuration of Chlorine is [Ne]3S23P5

Barium has 2 valence electrons and chlorine has 7 electrons in its valency shell.

Barium has to lose 2 electrons to get octet configuration and chlorine requires one electron to get octet configuration.

Formula of barium Chloride is BaCl​​​2

Part C:

Electronic configuration of Potassium: [Ar]4S1

Electronic configuration of Tellurium: [Kr]4d105S25P4

Potassium has 1 valency electron and to get octet configuration, it has to lose 1 electron.

Tellurium has 6 valency electrons and to get octet configuration, either it has to lose 6 electrons or gain 2 electrons.

Two Potassium atoms lose one electron each and one Tellurium atom gains these two electrons. Both the atoms, potassium and Tellurium gets inert gas configuration.

It's formula is K2Te

Part D:

Electronic configuration of Lanthanum : [Xe]5d16S2

Electronic configuration of oxygen : [He]2S22P4

Lanthanum has 3 electrons in its valency shell and oxygen has 6 electrons.

It's formula: La2O3

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