A photoresistor, whose resistance decreases with light
intensity, is connected in the circuit of the figure. On a sunny
day, the photoresistor has a resistance of 0.66 kΩkΩ . On a cloudy
day, the resistance rises to 4.0 kΩkΩ . At night, the resistance is
26 kΩkΩ
What does the voltmeter read on a sunny day?
What does the voltmeter read on a cloudy day?
What does the voltmeter read at night?
Does the voltmeter reading increase or decrease as the light intensity increases (in terms of current)?
Part A.
On a Sunny day, equivalent resistance of circuit will be
Req = 1.0 k-ohm + resistor of photoresistor
Resistor of photoresistor on sunny day = 0.66 k-ohm = 660 ohm
Req = 1000 + 660 = 1660 Ohm
Now We know from Ohm's law, that
ieq = V/Req = 9/1660 = 0.005422 Amp.
Now we know that in series circuit current in resistor will be equal to total current, So
current in 1 k-ohm = 0.005422 Amp
Voltage in this 1 k-ohm resistor will be
V = i*R = 0.005422*1000
V = 5.422 V
In two significant figures:
V = 5.4 V
Part B.
On a cloudy day, equivalent resistance of circuit will be
Req = 1.0 k-ohm + resistor of photoresistor
Resistor of photoresistor on cloudy day = 4.0 k-ohm = 4000 ohm
Req = 1000 + 4000 = 5000 Ohm
Now We know from Ohm's law, that
ieq = V/Req = 9/5000 = 0.0018 Amp.
Now we know that in series circuit current in resistor will be equal to total current, So
current in 1 k-ohm = 0.0018 Amp
Voltage in this 1 k-ohm resistor will be
V = i*R = 0.0018*1000
V = 1.8 V
Part C.
at night, equivalent resistance of circuit will be
Req = 1.0 k-ohm + resistor of photoresistor
Resistor of photoresistor at night = 26 k-ohm = 26000 ohm
Req = 1000 + 26000 = 27000 Ohm
Now We know from Ohm's law, that
ieq = V/Req = 9/27000 = 0.00033 Amp.
Now we know that in series circuit current in resistor will be equal to total current, So
current in 1 k-ohm = 0.00033 Amp
Voltage in this 1 k-ohm resistor will be
V = i*R = 0.00033*1000
V = 0.33 V
Part D.
From above we can see that as current increase (given light intensity increases) reading of voltmeter increases.
Let me know if you've any query.
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