Find a parametrization of the tangent line at the point indicated. r(t) = (1 - 4,...
Find a parametrization of the tangent line at the point indicated. r(t) = <1 − t4, 2t, 3t3> t = 2 L(t) = <−23t−15,2t+4,36t+24>
2. Find the parametrization of the tangent line to the space curve r(t) = (In(t), e6", –+2) at t= 1.
(1 point) Find a vector equation for the tangent line to the curve r(t) = (2/) 7+ (31-8)+ (21) k at t = 9. !!! with -o0 <1 < 0
13. (5 points) parametrization Find an equation of the tangent line to the curve given by the =t- - y = 1+12 at t=1.
2. Consider the surface S with parametrization r(s, t)< st, s,t3 - s >. Find parametric equations and symmetric equations for the tangent plane to S at the point (1, 1,0).
2. Consider the surface S with parametrization r(s, t). Find parametric equations and symmetric equations for the tangent plane to S at the point (1, 1,0).
(4) Evaluate the line integral F dr where C is the epicycloid with parametrization given by r(t) 5 cos t - gradient of the function f(x, y) = 3 sin(ry) + cos(y2) cos 5t and y(t) = 5 sin t - sin 5t for 0 < t < 2« and F is the (5) EvaluateF dr where F(x, y) with counterclockwise orientation (2y, xy2and C is the ellipse 4r2 9y2 36 _ F dr where F(r, y) = (x2 -...
12.1.24 Question Help The tangent line to a smooth curve r(t) = f()i + 96)j + h(t]k at t= to is the line that passes through the point (f(t):(to)."(to) parallel to (to)the curve's velocity vector at to User (to) and (t) to find parametric equations for the line that is tangent to the given curve at the given parameter value t= to (1)-(31²)i + (4 + 3)j + (52) 10-3 What is the standard parametrization for the tangent line? yo...
(1 point) Find the distance of the point (2,4, -4) from the line r(t) = (1 + 2t, 1 + 4t, 3 – 3t). Answer:
(1 point) Find the slope of the tangent line to the polar curve
?=cos(4?)r=cos(4θ) at the point corresponding to ?=?/3θ=π/3.
The tangent line has slope
(1 point) Find the slope of the tangent line to the polar curve r = cos(40) at the point corresponding to 0 = a/3. The tangent line has slope
Find the unit tangent vector T(t) at the point with the given value of the parameter t. r(t) = (2 – 3t, 1 + 4t, 582 + 2x2), t = 4 T(4) = <5,4,720 > 720.02847 x