Question

In the circuit below, Vin is a function generator that outputs a sinusoidal waveform. For calculations with complex numbers, using an engineering calculator or Matlab is recommended. C = 680F HH ZR R = 18212 - 92 V = 5V 2-45 f=130Hz

Answer 1

Solution 122.. Cq R2 mm RI Vout. + Ven= 51-45 in volt f = 130 HZ Given, Z, = R1 = (9K-2-20) And, Rx = 18 g , ca 268nf » XC2 = j 27fC2 -j » Xc2 215x 130 x 68 x109 XC2 1. Ia 18100 X-118000 -j 18 km (RQ 11 jx2) - Rax-jXc2 x-j180 Ra-jXc2 18000 -j 18000 = 9000 - 39000 =Z2 = 12727.924-45. ohm eus The given op-Amp circuit reduced to below; 렸 I 2 Z Vin + 1 Vout we know, (Inverting op-Amp) know, for for Enverting op-Amp. Vout » Vout (127271924-45°) (9000 Loo -72 Vin II 51-454 > Vout .6363906 1-900 9000

* Vout a - 70076-909 volt * Vout a -(0-17.07) » Vout = 17.07 Voret = 7007290° volts sw= Given frequency (f) = 130 HZ Angular frequency (w) = 2074 = 295*130 w = 816.4 rad/see 19> Magnitude of Vocet is Voret (oms) = 7007 volts phase of voet is p = 90° th> Vout () Um sin (wfto) vort (t) = 7.07 17 sin ( 316.47 +909) Voret (t) = 10 sên (816.4t +909) volts Vin = 5rã sin(816.4t - 45°) Vin = 7.07 sin ( 846047-459) volte

دعا Vin ا ، وht *مه 45° 90° 180 'م# 360" 04 مژه Voutt (0V م19 ,96- 90' a7o" وه ۸۹۱

Assumed Vin =5 V(rms value)

Magnitude and phase of Vout is 7.07(rms value) and 90° respectively.

Vout(t) = 10 sin(816.4t+90°)=10 cos(816.4t)