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Q1: Consider two particles occupying the ground state 01) and the first excited state (42) of the one dimensional infinite sq
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Answer #1

a) If the particles are distinguishable, then let the first particle be in the ground state and the second particle be in the first excited state. This state is represented as

121, 12) = V12102(22)

Another possibility is the first particle be in first excited state and the second particle is in the ground state. This state is represented as

111, 12) = 02(11)01.22)

b) If the particles are identical then either particle can be in ground state or first excited state. For bosons, the wave function is symmetric and the normalization factor is 1/sqrt(2).

1 (11, 12) = 5 (01 (21)\\?(x2) + 42(71)41 (x2))

c) For identical fermions, the wave function is anti-symmetric and the normalization factor is 1/sqrt(2).

((Tx}iâ(17)īci – (Tx)=f(12)T™) 9 = (+212)

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