Question

A beam of initially unpolarized light passes through a sequence of three ideal polarizers. The angle between the axes of the and second polarizers, labeled P12, is 22.1° and the angle between the axes of the second and third polarizers, labeled 023, 53.3°. What is the ratio of the intensity of light emerging from the third polarizer, 13 , to the intensity of light incident on the first polarizer, I ? A beam of unpolarized light shines on a stack of five ideal polarizers, set up so that the angles between the polarization axes of pairs of adjacent polarizers are all equal. The intensity of the transmitted beam is reduced from the intensity of the initial beam by a factor of $ = 0.103. Find the angle between the axes of each pair of adjacent polarizers.

Answer 1

Incident light intensity = I. intensity after 1st polarizer T, - I intensity after and polarizer I - II costo (Malustaw). I, - Te cose (22.1") intensity after svd polaregen ✓ = Icoses cos (22.1) cose (53.3') (0.926)*(0.5976) => (0.9261)* Co. 15976)2 = 0.1533 2 2. initial incident = I after ist polarizer F = I after suck polarijer I, - Il caso de costo after grad polarejet Ig - I., Coge = te costo after alla polarizer It Is cesc = I cogebog after siti polarijer FG = If costo - f caso Given that 15 = $ = 0.103 => in corpo - 0.103 cosso = 2X0-103= 0.206 coso = (0.206)/8 = 0.8208 0 = Cos! (0-8208) = 34.8°