1/wavelength = RH [1/2^2 - 1/n^2]
where RH = 1.0967 x 10^7 m^-1
1/(410x 10^-9) = (1.0967 x 10^7) [ 1/4 - 1/n^2]
1/4 - 1/n^2 = 0.2224
1/n^2 = 0.0276
n = 6
Question 5 2 pts Suppose the wavelength in the formula developed by Balmer was 410 nm....
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0.41 246 Question 15 5 pts Athin layer of oil (n = 1.40) floats on the surface of a puddle of water (n = 1.33). One part of the oil film appears bright greenish-blue, i.e. it strongly reflects light with a wavelength in vacuum of 497 nm. What is the smallest nonzero film thickness of the oil film in this region? 207 nm O 89.0 nm 124 nm 249 nm 178 nm U Question 16 5 pts Use the Bohr...
Question 16 5 pts Use the Bohr model to find the second longest wavelength of light in the Balmer series for a triply- ionized Be atom (Z = 4). Recall that the Balmer series corresponds to transitions to the n = 2 level. 30.4 nm 117 nm 73.0 nm 41.1 nm 209 nm
Question 16 5 pts Use the Bohr model to find the second longest wavelength of light in the Balmer series for a triply-ionized Be atom (Z = 4). Recall that the Balmer series corresponds to transitions to the n = 2 level. 30.4 nm 117 nm 73.0 nm 41.1 nm 209 nm
Use the Balmer formula to calculate the first four wavelengths, in nm, of the spectrum corresponding to n = 3, 4, 5, and 6. show the details of your work.
Use the Bohr model to find the second longest wavelength of light in the Balmer series for a triply-ionized Be atom (Z = 4). Recall that the Balmer series corresponds to transitions to the n = 2 level. O 30.4 nm O 117 nm 0 73.0 nm 0 41.1 nm 209 nm
Use the Bohr model to find the second longest wavelength of light in the Balmer series for a triply-lonized Be atom ( Z4). Recall that the Balmer series corresponds to transitions to the n = 2 level. 30.4 nm O 117 nm 73.0 nm 41.1 nm 0 209 nm
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