MW of Al = 26.98 g
MW of Mg = 24.305 g
then
ratio ---> 24.305 /26.98 = 0.90085 g of Mg per 1 g of Al
then,, if m = 9 g of Al
0.90085*9 = 8.10765 g
as stated,
1 mol of Al = 1 mol of Mg = 6.022*10^23 atoms
therefore
this is true
since each atom weighs different
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