Question

Problem 3: An object is thrown vertically up with a speed of (20 + 0.5x) m/s from a height of (15 + x) m. (a) What is the maximum height it will attain? (b) How long will it be in air? (c) Sketch its velocity vs. time graph

Answer 1

Answers uz 204 0.5*6 = 23 mis Į using Į S=utt £ at ² u Tu v2=u2+ zas h=21ml for mascimum height v=0 La 9-tomisa CO) = (23)2 - 2x10XH . H= (2372 529 = 26.45m Zo s 20 = 26.45m Hmar oht H = 47.45m 3 ① s= ut + h at2 , 5=-2/m u=22mis = 21=23t-st2 a=10m/s² st²_231-21=0 ta 23+) (23)2 485 XC-21) 2343080 2X5 It=5.38 seol 10

V ml 23 mil i tosec t-= 2:38. t=5.38 sec.