Question

-/3 points HRW6 12.P.007. A uniform sphere rolls down an incline. (a) What must be the incline angle if the linear acceleration of the center of the sphere is to have a magnitude of 0.20g? (b)lf a frictionless block were to slide down the incline at that angle, would its acceleration magnitude be more, less than or equal to 0.20g? The acceleration magnitude would be equal to 0.20g. The acceleration magnude would be more than 0.20g. O. The acceleration magnitude would be less than 0.20g. Why?

Answer 1

Sol: A body slides down on a tilted frictionless plane, then it experiences a force along the inclined surface in the downward direction Force (E) = mg sino. I E = mg sino F=ma cauration is Consider the tonaue fraica) f = ena mgsing - ema = ma Inclination angle is o = sin (7a) or sin (7x0.20g) os sin! (7 XO 20) O 16.2°

b) angle planen force canation along inclined 1 mg sino = ma a= g sino Kg sino = xg sino g sin (16.2) = a (a = 0.279 The magnitude would be more acceleration than 0.20g.