Question

mass is 162 g/mol. What are the empirical anu mom lar formulas of nicotine? etermining Formulas from Mass Data e Examples 2.10 and 2.11.) 3. A compound containing xenon and fluorine was pre- pared by shining sunlight on a mixture of Xe (0.526 g) and excess F2 gas. If you isolate 0.678 g of the new compound, what is its empirical formula? Elemental sulfur (1.256 g) is combined with fluorine, F2, to give a compound with the formula SF,, a very stable, colorless gas. If you have isolated 5.722 g of SI what is the value of x? Epsom salt is used in tanning leather and in medicine is hydrated magnesium sulfate, MgSO, 7 HOT

Answer 1

5.22 la mau? in sfise = 100-21-9 = 78.05%. view WLOA xe = nC264 Given Elemental sulphus combined i and man of new 1 with fluorine & % compound = 0.6789 mars Sfx = 5.7239 Now, may of s = 1.256g Keº 22 Xe= 0 s26 + = 0-00401 1 3129 gimo moles mau% of s uń Sfx = (1-256, ) x100 moles of f= 6:6789-0-5269) 19% 21.9% gime of mee = 0.008 moles Mence, empenical formula moles 9 S = 21.99x Imoles 01684 moles will be in ratio of 1:2. 3295 moles ff = 78.05 F ximol F = 4.108 o xe and I respectively. Dividing by smallest mole, og de xef S = '0.684 | ...PSXe :f = 0.004: 0.0087 si 0.68472 1:2 Txer fa f = 40108 } 6 0.684 . Hence, emperical formula is SF6 Now, 19.09F molf