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2. The following distribution represents the ratings (from 1 to 5 stars) for a product sold online. The random variable X is
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P(x) 04. 03 .22 5 53 E(X)= Ex.Pcs - 1x04 + 2X-03 + 3x.22 +4 X 18 +5X53 = .04t.o6t66 +0.72 +2.65 - 4:13 L (9) On average, howI ove for 2 8 ters? Oce PLAUB)= P(x) + P(X2) 2.04 .03 - 07 would it be cmurual for the - No product I in highest which d) P(5

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