What is the maximum possible acceleration on the platform?Homework Answers
From the first two part of the solution it is clear that T1 is larger than the T2 for constant acceleration 'a'. It means if we increase the acceleration first T1 will become 70N and then break.
So we need to find out what will be accelation when T1 is equal to 70N.
So put T1 = 70N in part 1 we have
70N = mtotalamax + mtotalg = 5.2 x amax + 5.2 x 9.8
So amax = 3.66 m/s2
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What is the maximum possible acceleration on the platform?
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kg are fastened to the top of an elevator as in the figure.
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please show all...
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