23. The volume of a carbon dioxide molecule is 9.336 x 10-26 liters. If a 0.157...

Question

Question

Answer 1

Answer #1

Using ideal gas equation

PV = nRT

n = 1.15×0.157/0.0821×305

= 0.00721 mol

Number of CO2 molecules = 0.00721×6.023×10²³ = 4.34×10²¹ molecules

Total volume occupied by CO2 molecules = 4.34×10²¹×9.336×10^-26 => 4.05×10^-4 L

Percentage volume occupied = 4.05×10^-4 ×100/0.157

= 0.258%

Answer 2

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