Question

III P Flag question Select the correct answer of horizontal deflection (mm) for joint C by using virtual method. Assume A= 250 mm? and E =200 GPa. SkN c 2 m 1.5 m 10 kN NOTE KOWO POLE TINSON FOR 5kw C 125 (T) CLOON IN ZA on o 10 KN FORES VIRTULIS Select one: a. 0.469 b. 0.268 c. 0.313 d. 0.375

Answer 1

Only the forces in member CB will count towards horizontal deflection at C as the virtual forces in other members is zero

Real force in member CB = N = 12.5 kN = 12500 N

Virtual force in member CB = n = 1 N

Therefore horizontal deflection at C is given as

$\Delta =\sum \frac{nNL}{AE}$

$=\frac{(12500)(1)(1500)}{250(200\times 10^{3})}$

= 0.375 mm

Hence option 'd' is correct