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Bo R = 0.28 R = 0.35 R = 0.38 to R = 0.22 Model A: Model B: log(y) 5.65 + 0.75 x1 0.34 0.25 x1 Model C: log(y) Model D: y 0.3

Can we use R^2 (R-squared) to compare these models? Why or why not?

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Answe8:- (O.) 10* b, Ay = - 10*0.75 = 7:5 (b) level log it means uhen x, is changed by 1 ur y Will change by regression 25/.

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