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Deduce trignometric identity 6B (tan A- tan B) Identity 6B: tan (A - B) = 1 + tan Atan B Using sin (A-B) = sin A cos B - cos
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COSA.sinB SOL:- tan (A-B) = sin(A-B) COSCA-B) sin A. COSB COSA.sinB COSA.COSB + sinA.sinB How divide all terms by cos Acosß ssing tan ( (A-B) - sina COSA COSB 1 + sinA SinB COSB COSA ( tan A - tanB) 1+tan A dan B #please rate the solution by thumb ? 100 %

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