Question

An electron is at the origin. (a) Calculate the electric potential VA at point A, X = 0.310 cm. (b) Calculate the electric potential V, at point B, x = 0.510 cm. What is the potential difference V-VA? (c) Would a negatively charged particle placed at point A necessarily go through this same potential difference upon reaching point B? Ex This answer has not been graded yet. Need Help? Read it

Answer 1

Given is:-

Charge  

q= -1.6 x 10-19

Now,

part - a

Electric potential is given by

Kq V =

by plugging all the values we get

(9 x 10 (-1.6 x 10-19) 0.310 x 10-2m

which gives us

VA = 4.646 x 10-7V

Part - b

Similarly

VB = (9 x 10 (-1.6 x 10-19) 0.510 x 10-2m

which gives us

VB = -2.824 x 10-7V

Part - c

The required potential difference will be

VB - VA= -2.824 x 10-7V -(-4.646 x 10-7V)

which gives us

VB - VA = 1.822 x 10-7V

Part - d

No,

Unless fixed in place, the electron would move in the opposite direction, increasing its distance from point A and point B and lowering the potential difference between them