Question

Use d = proj QP to find the distance between point P(5, 3, – 4) and the plane given by QRXOS 6x+2y- z-5=0.

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Answer #1

Use projection formula we can have the distance between a point and a plane.

Let, Q(x, y, z) be the point in the given plane 6x+ry-2-550. A points PCS, ,-4) outside plane Qp = (5-X, ,317,-4-2) =<6,2,-4)please ask for any doubt and rate if u satisfied

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