Accoridng to the given problem,
[Given]Final KE = 0.5*m*v2
= 0.5*0.246*2.352 J = 0.68 J
So the energy supplied by the battery must be 3.00J / 0.416 =
1.633J
1.633 J is an average power of 1.633 W for 1 second.
Over 7.88 s the average power is therefore 1.633 Ws / 7.88s =
0.2072 W
And Using the power formula,
P = V * I
so the average current is I = P/V = 0.2072W / 1.5V = 0.138 A
I hope you understood the problem, If yes rate me!! or else comment for a better solution.
Gra 0/201 8 11:59 PM ?55/10003/28201 80807 PM Periocio Table Mup apling Learning A 0.246-kg toy...