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5. Both CrBr2 and MnBr2 have a central metal cation surrounded by six bromide anions. One of them shows the equidistant bond
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Answer #1

Br is a weak field ligand hence it forms high spin complex

MnBr2 : Mn is in +2 oxidation state and Mn2+ is d5 with configuration t2g3 eg2 since both the orbitals are symmetrically filled hence it would be perfectly octahedral with equal Mn-Br bond length

whereas CrBr2 is Cr2+ is having d4 ion with t2g3eg1 configuration in which eg set is unsymmetrically filled due to which Jahn Teller distortion takes place and the geometry will not be perfectly octahedral due to which we get unequal bond length

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