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Determine the kinetic energy of a gas at temperatu

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Question-8 : The kinetic energy of a gas at temperature 90 degree celsius, which is given as -

using an equation, we have

K.E = (3/2) k T

where, k = 1.38 x 10-23 J/K

T = temperature = 90 0C = 363 K

then, we have

K.E = (3/2) (1.38 x 10-23 J/K) (363 K)

K.E = 751.4 x 10-23 J

K.E = 7.51 x 10-21 J

Question-10 : Her initial moment of inertia was given as -

using conservation of angular momentum,

I1\omega1 = I2\omega2

I1 (9.42 rad/s) = (0.88 kg.m2) (25.1 rad/s)

I1 = (22.08 kg.m2 rad/s) / (9.42 rad/s)

I1 = 2.35 kg.m2

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