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The buildup of plaque on the walls of an artery may decrease its diameter from 1.1...

The buildup of plaque on the walls of an artery may decrease its diameter from 1.1 cm to 0.71 cm. The speed of blood flow was 14 cm/s before reaching the region of plaque buildup.
(a) Find the speed of blood flow within the plaque region.
cm/s

(b) Find the pressure drop within the plaque region. (Assume the density of blood is 1060 kg/m3.)
Pa
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Answer #1

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Answer #2

Q = A1V1 = A2V2 = pi(.011/2)^2 x 0.14 m/s =pi (0.0071)^2 *V2

V2 = = 0.047 m/s

Per Bernoulli: P1/gamma + .14^2/2g = P2/gamma + .0.047^2/2g
Density of blood, gamma = 1060 kg/m^3
Therefor, the pressure drop is P1-P2 = gamma g x .017391/2g
= .0086955 m^2/s^2 (1060)
= 9.21723 kg/m*s^2 = 9.21723 Pa

Notice two things: 1. the g's cancel out, and 2. Pa = N/m^2
= kg m/s^2/m^2
= kg/m*s^2

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